exception handling - Python try/except: Showing the cause of the error after displaying my variables

Question

I'm not even sure what the right words are to search for. I want to display parts of the error object in an except block (similar to the err object in VBScript, which has Err.Number and Err.Description). For example, I want to show the values of my variables, then show the exact error. Clearly, I am causing a divided-by-zero error below, but how can I print that fact?

try: 
    x = 0 
    y = 1 
    z = y / x 
    z = z + 1 
    print "z=%d" % (z) 
except: 
    print "Values at Exception: x=%d y=%d " % (x,y) 
    print "The error was on line ..." 
    print "The reason for the error was ..." 

question from:https://stackoverflow.com/questions/4560288/python-try-except-showing-the-cause-of-the-error-after-displaying-my-variables

Answer 1

try:  
    1 / 0 
except Exception as e: 
    print(e)