linux - How to store the result of an executed shell command in a variable in python?

Question

I need to store the result of a shell command that I executed in a variable, but I couldn't get it working. I tried like:

import os    

call = os.system("cat syscall_list.txt | grep f89e7000 | awk '{print $2}'")
print call

But it prints the result in terminal and prints the value of call as zero, possibly indicating as success. How to get the result stored in a variable?

question from:https://stackoverflow.com/questions/8659275/how-to-store-the-result-of-an-executed-shell-command-in-a-variable-in-python

Answer 1

Use the subprocess module instead:

import subprocess
output = subprocess.check_output("cat syscall_list.txt | grep f89e7000 | awk '{print $2}'", shell=True)

Edit: this is new in Python 2.7. In earlier versions this should work (with the command rewritten as shown below):

import subprocess
output = subprocess.Popen(['awk', '/f89e7000/ {print $2}', 'syscall_list.txt'], stdout=subprocess.PIPE).communicate()[0]

---

As a side note, you can rewrite

cat syscall_list.txt | grep f89e7000

To

grep f89e7000 syscall_list.txt

And you can even replace the entire statement with a single awk script:

awk '/f89e7000/ {print $2}' syscall_list.txt

Leading to:

import subprocess
output = subprocess.check_output(['awk', '/f89e7000/ {print $2}', 'syscall_list.txt'])