How to reverse a given number in python using just for loop

Question

i did it in while loop but couldn't do it in for loop

my code using while loop :

x=int(input("enter a number: "))
i=0
while(x>0):
    remainder=x%10
    i=(i*10)+remainder
    x//=10
print(i)

question from:https://stackoverflow.com/questions/65640864/how-to-reverse-a-given-number-in-python-using-just-for-loop

Answer 1

In your example your using arithmetic, but why not convert to a string to make life easier?

x = int(input("enter a number: "))
result = ""
for char in str(x)[::-1]:
  result += char
print(result)

Note that [::-1] means "iterate backwards" and that if your number ends with zeros, they'll appear at the start of the reversed string. If you want, you can trim them with lstrip:

print(result.lstrip("0"))