Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
544 views
in Technique[技术] by (71.8m points)

client - Can I program a server which doesn't close?

I tried to write a client-server system in which the server is executing commands that the client sends to it. There are 4 possible commands:
NAME - returns the server's name.
TIME - returns the current time.
RAND - returns a random number between 1 to 10.
EXIT - disconnects the server-client communication.

After one of the commands is executed - the server closes the client's and the server's sockets.
Is there a way to keep the connetion "opened" and to continue sendind commands?
I've already tried to remove the next lines from the server code:

client_socket.close()
server_socket.close()

Here's the server code:

import socket
import time
import random

def main():

    server_socket = socket.socket()
    server_socket.bind(('0.0.0.0', 8820))

    server_socket.listen(1)

    (client_socket, client_adress) = server_socket.accept()

    client_input = client_socket.recv(1024).decode()

    if client_input == 'TIME':
        client_socket.send(str(time.asctime(time.localtime(time.time()))).encode())
    elif client_input == 'NAME':
        server_name = 'server2.6'
        client_socket.send(server_name.encode())
    elif client_input == 'RAND':
        client_socket.send(str(random.randint(0, 10)).encode())
    elif client_input == 'EXIT':
        client_socket.close()
        server_socket.close()
        pass
    else:
        error_message = 'Not one of the options'
        client_socket.send(error_message.encode())

    client_socket.close()
    server_socket.close()

if __name__ == '__main__':
    main()

And here's the client code:

import socket

def main():

    my_socket = socket.socket()
    my_socket.connect(('127.0.0.1', 8820))
    options = ['NAME', 'TIME', 'RAND', 'EXIT']
    is_legal_option = False
    while is_legal_option == False:
        client_input = input('Enter your command (NAMETIMERANDEXIT): ')
        if len(client_input) != 4:
            print("The command must be 4 letters.")
            continue
        if client_input.isupper() == False:
            upper_client_input = client_input.upper()
            client_answer = input("If you meant: '" + upper_client_input + "', enter '1', else enter '2'")
            if client_answer == '1':
                client_input = upper_client_input
        for x in options:
            if client_input == x:
                is_legal_option = True
                break
        if is_legal_option == False:
            print("Not one of the options.")
    my_socket.send(client_input.encode())
    data = my_socket.recv(1024).decode()
    print (data)
    my_socket.close()


if __name__ == '__main__':
    main()
question from:https://stackoverflow.com/questions/65939409/can-i-program-a-server-which-doesnt-close

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
Waitting for answers

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...