php - Why am I getting this invalid parse?

Question

I have an Ajax function to load all columns names and their values via php as follow:

PHP SIDE:

$res = $db->query($stmt);
$rsltz= array();
while ($row = $res->fetchArray(SQLITE3_ASSOC)) {
    foreach ($row as $colonne => $valeur) {
      $rsltz[$colonne] = isset($valeur) ? $valeur : ""; 
    }
}
header('Content-type: application/json');
echo (json_encode($rsltz));

AJAX FUNCTION:

function jet(a,b,c){
$.ajax({
        type: 'POST',   
        cache: false,           
        url: 'builder.php',
        data:  { typ:a, lg:b ,menu:c},
         success: function(result) { 
             if(typeof(result) === "string") {
                $('#par').after(result);
              } else {
                //JSON hier comes a loop to display key=>val
                var pars = JSON.parse(result); 
             $('#par').after(pars.datasrc);
              }          
        },
        error: function (jqXHR, textStatus, errorThrown) {
        alert(jqXHR+'
'+textStatus+'
'+ errorThrown);
        }
});
}

I have this error:

here the json.encoded result :

{"id":"510","menu":"regis","taketo":"regis1","auth":"ALL"}

I do appreciate any help ?.

question from:https://stackoverflow.com/questions/65937587/why-am-i-getting-this-invalid-parse

Answer 1

We don't have to re-parse what is already parsed! The response (result in Ajax function) IS already parsed. So just use it as it is:

var pars = JSON.parse(result); 
$('#par').after(pars.datasrc);

has to be replaced with

$('#par').after(result.datasrc);

Thank you guys.