linux - awk string substr and cut not need char

Question

I need to delete some char on string, example I have this string

$ tst=/oracle/orcl/dbms1911c
$ printf '%s' ${tst} | awk -F'/' '{print substr($4,5,6)}'
$1911c

How can I remove the 11 and my output will be 19c? I want only this when the string is not 19c.

Thanks in advance

question from:https://stackoverflow.com/questions/65924439/awk-string-substr-and-cut-not-need-char

Answer 1

Based on your shown samples, could you please try following.

1st solution: Create a variable with substr of awk and then play with it to get exactly needed shown value, this approach will be useful in case we need to use this variable for further in the program too. Where tst=/oracle/orcl/dbms1911c is the variable's value as per shown samples.

printf '%s' ${tst} | 
awk -F'/' '{val=substr($4,5,6);print substr(val,1,2) substr(val,5)}'

2nd solution: Without using a variable and using substr itself, though I feel 1st approach is BEST that variable could be used for other tasks also, for fun and as an another option adding this one.

printf '%s' ${tst} | 
awk -F'/' '{print substr(substr($4,5,6),1,2) substr(substr($4,5,6),5)}'

3rd solution: or try this substr also here like:

printf '%s' ${tst} | 
awk -F'/' '{print substr($4,5,2) substr($4,9)}'