I have a django application. when a user clicks the submit button two modals should be shown one after another each has to do different functions in views.py in my django app. I am trying to write the code but the problem is not easy and I have looked everywhere and couldn't get the answer.
I have to write the code in the following way:
views.py
def submit(request):
#first modal should pop up which has two options.
#secound modal should pop up which also has a two options.
and when the user clicks any of the buttons each should also call the different function in views.py.
html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<button class="btn btn-danger custom" style="position:absolute; left:800px; top:180px;" type="submit">Update the data</button>
# user clicks a button in form and modal should pop up
# then 2 modals should pop up
# the first modal has two buttons
# when user clicks the update button the function in the views should be called and also 2nd modal
should pop up
<!--modal 1-->
<div aria-hidden="true" aria-labelledby="exampleModalLabel" class="modal fade" id="UpdateModal" role="dialog"
tabindex="-1">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="exampleModalLabel">Update Changes</h5>
<button aria-label="Close" class="close" data-dismiss="modal" type="button">
<span aria-hidden="true">×</span>
</button>
</div>
#when user clicks update button another modal should pop up as well as
another function in the views should be called.
</body>
</html>
question from:
https://stackoverflow.com/questions/65914399/how-can-i-open-a-modal-from-views-py-in-django-is-there-any-way 与恶龙缠斗过久,自身亦成为恶龙；凝视深渊过久,深渊将回以凝视…
