C++ Int array type in function call

Question

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. question from:https://stackoverflow.com/questions/65908784/c-int-array-type-in-function-call

Answer 1

If the array passed to the function is known beforehand, in this case as int example[5][5];, you can use the following,

void example_function(int (&inArray)[5][5], int z){
    cout << "example text = " << inArray[z][z] << endl;
}

Here we take the array by reference to avoid array decay.

If the size might vary at runtime, use std::vector.

std::vector<std::vector<int>> example;

void example_function(std::vector<std::vector<int>> inArray, int z){
    cout << "example text = " << inArray[z][z] << endl;
}