Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
901 views
in Technique[技术] by (71.8m points)

fortran - MPI_Recv overwrites parts of memory it should not access

In the following code the value of xysize gets changed, if I do not declare it as a parameter (which I generally cannot do). It happens only with optimizations -O2 and more in gfortran 4.7.2 and OpenMPI 1.6. How is it possible? I cannot find the exact interface, that I import from mpi.mod, but the C prototype clearly states that count is passed by value, hence it cannot change.

     write(*,*) im,"receiving from",image_index([iim,jim,kim+1]),"size",&
      size(D%A(D%starti:D%endi,D%startj:D%endj,D%endk)),xysize

    call MPI_RECV(D%A(D%starti:D%endi,D%startj:D%endj,D%endk+1),xysize , MPI_REAL, image_index([iim,jim,kim+1])-1,&
           5000, comm, status, ierr)

    write(*,*) im,"received size",&
      size(D%A(D%starti:D%endi,D%startj:D%endj,D%endk)),xysize

output:

1 receiving from           2 size        4096        4096
1 received size        4096        5000
Question&Answers:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

For the sake of future visitors, I suppose I'll answer this even though it's all answered in the comments above.

As far as I'm aware, if your program is behaving properly, you cannot change the value of that parameter ("count") in a call to MPI_Recv.

Your argument status is too small, it should be an array status(MPI_STATUS_SIZE), and you're getting a buffer overflow -- This often results in a segmentation fault, but at times (depending on how the compiler packed the variables in memory), it can result in funny behavior like this.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...