c - Pass the char* directly to printf

Question

#include <stdio.h>

char s[]="sfksfls
";
void main()
{
        printf(s);

}

Why it can work? I just input the char pointer to printf

Answer 1

A string literal in C is a pointer to const char. printf takes a pointer to const char (plus an optional list of additional arguments). Passing it directly or through a variable makes no difference, a pointer is a pointer, it's just a number.