As part of our training in the Academy of Programming Languages, we also learned C. During the test, we encountered the question of what the program output would be:
#include <stdio.h>
#include <string.h>
int main(){
char str[] = "hmmmm..";
const char * const ptr1[] = {"to be","or not to be","that is the question"};
char *ptr2 = "that is the qusetion";
(&ptr2)[3] = str;
strcpy(str,"(Hamlet)");
for (int i = 0; i < sizeof(ptr1)/sizeof(*ptr1); ++i){
printf("%s ", ptr1[i]);
}
printf("
");
return 0;
}
Later, after examining the answers, it became clear that the cell (& ptr2)[3] was identical to the memory cell in &ptr1[2], so the output of the program is: to be or not to be (Hamlet)
My question is, is it possible to know, only by written code in the notebook, without checking any compiler, that a certain pointer (or all variables in general) follow or precede other variables in memory?
Note, I do not mean array variables, so all the elements in the array must be in sequence.
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