xml - how to add break line in xmllint command

Question

posted Jan 31, 2022 in Technique[技术] by 深蓝 (71.8m points)

I have the following command

xmllint --xpath "//*[local-name()='softwareSystem']/module/rootPath[not(@*[local-name()='type'])]/@name" file.xml

and would like to sperate each module (every matching) on a new line

thanks for help

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1 Reply

深蓝 · Answer 1 · 2022-01-31T07:21:30+0000

I don't have your html so I have to guess, but with xmlstarlet, for example, try something like:

xmlstarlet sel -t -m "//*[local-name()='softwareSystem']/module/rootPath[not(@*[local-name()='type'])]" -v $'concat(@name,"
")' file.xml

or

xmlstarlet sel -t -m "//*[local-name()='softwareSystem']/module/rootPath[not(@*[local-name()='type'])]" -v $@name file.xml -n file.xml

and see if it works.