java - read exactly a string in the next line after maching the condition

Question

I have this simple and I am trying to find the string all and after finding it it should jump to next line and look for the integer value 30 and store it in Integer variable.

Simple:

spoon 05:09 05:39 06:11 06:41 07:11 07:41 08:11 17:11 17:41 18:11 18:41 19:11 19:41
apple 05:09 05:39 06:11 06:41 07:11 07:41 08:11 all 17:11 17:41 18:11 18:41 19:11 19:41
chair 05:11 05:41 06:14 06:44 30 07:14 07:44 08:14 17:14 17:44 18:14 18:44 19:14 19:44
table 05:13 05:43 06:17 06:47 07:17 07:47 08:17 Min 17:17 17:47 18:17 18:47 19:17 19:47

Code:

        Scanner scanner = new Scanner(file)) {
    int lineNum = 0;
    while (scanner.hasNextLine()) {
        String line = scanner.nextLine();
        lineNum++;
        if(line.contains(" all ")){
            //go to the next line and find the integer value 30 then store it.
            System.out.println("I found it on line " +lineNum);



        }

Answer 1

You can do something like this:

Scanner scanner = new Scanner(file)) {
int lineNum = 0;
while (scanner.hasNextLine()) {
    String line = scanner.nextLine();
    lineNum++;
    if(line.contains(" all ")){
        scanner.nextLine(); // this will skip to the next line
        System.out.println("I found it on line " +lineNum);
        // look for the integer value 30 and store it in Integer variable.
    }

Basically all you have to do is once the line contains the all word then you call scanner.nextLine() which will bring you to the next line and then after that you can look for 30 and then store it. Once you're finished if there's nothing left for you to do then you can call break; to exit the while loop