how do you delete the nth element in a list in Haskell

Question

How to write the implementation for the function which takes a number n and a list and removes the element at position n from the list. For example: remove 0 [1, 2, 3, 4] = [2, 3, 4]

Here is my attempt:

import Data.List.Split
remove :: Int -> [a] -> [a]
remove xs = let remove n xs = let (as, bs) = splitAt n xs in as ++ tail bs

But it doesn't work and shows me "Variable not in scope". Does anyone know how to fix it? Appreciate!!

Answer 1

I wrote a pretty intuitive recursive approach:

remove :: Int -> [a] -> [a]
remove _ [] = []
remove 0 (x:xs) = xs
remove n (x:xs) = x : remove (n-1) (xs)

Take into account that I am considering the first element to be index 0. Let me know if you have any doubts.