sorting - How to sort/order tuple of ip address in python

Question

kindly help me out to address IP address sorting

Input IP address:

[{'host': u'10.219.1.1'}, {'host': u'10.91.1.1'}, {'host': u'10.219.4.1'}, {'host': u'10.91.4.1'}]

Expected Output IP address:

[{'host': u'10.91.1.1'}, {'host': u'10.219.1.1'}, {'host': u'10.91.4.1'}, {'host': u'10.219.4.1'}]

Answer 1

You can do it like this:

a = [{'host': u'10.219.1.1'}, {'host': u'10.91.1.1'}, {'host': u'10.219.4.1'}, {'host': : '10.91.4.1'}]

sorted(a, key=lambda x: tuple(int(i) for i in x['host'].split('.')))

# [{'host': '10.91.1.1'}, {'host': '10.91.4.1'}, {'host': '10.219.1.1'}, {'host': '10.219.4.1'}]

sorted(a, key=lambda x: tuple(int(i) for i in x['host'].split('.'))[::-1])

# [{'host': '10.91.1.1'}, {'host': '10.219.1.1'}, {'host': '10.91.4.1'}, {'host': '10.219.4.1'}]