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in Technique[技术] by (71.8m points)

python - return and print does not give same result

what I'm trying to do is take the entered string separated by commas and change it to list then for each list as a key print the associated value.

def main():
    myDict = {'a':1, 'b':2, 'c':3, 'd':4, 'e':5....}
    u_input = input("Enter a letter")
    myList = [x.strip() for x in u_input.split(',')]
    result = searchDict(myList)
    print(result)

def searchDict(key):
    for ml in key:
        value = myDict.get(ml, "not found")
        re = []
        re.append(value)
        print('-'.join(re)) #this one shows each value for each entered key separated by comma but it does not print it in one line also prints 'None' on the end

    #res = '-'.join(re)
    #return res //this only shows the value for the first key only even if I enter multiple letter

main();

The prob is that, if I return 'res' instead of printing it, I'm only getting the first key value.

output with print(if I enter a, b): 1, 2, none

output with return 1

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0 votes
by (71.8m points)

Are these lines indented properly?

for ml in key:
value = myDict.get(ml, "not found"); 
re = [];
re.append(value)

I think you want it to do this:

re = []
for ml in key:
    value = myDict.get(ml, "not found")    
    re.append(value)
return '-'.join(re)

BTW no semicolons used in Python.


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