Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
894 views
in Technique[技术] by (71.8m points)

Invalid syntax---python

I can't figure out why it is saying invalid syntax for the word Options in all of my If statements

Options = raw_input("Would you like to Square, Cube, Multiply, or Divide?    ")


If  Options == "Square" or Options == "square":
Square = int(raw_input("What number would you like to Square?    "))
Answer1 = Square ** 2
print "The answer is :%d" %Answer1

if Options == "Cube":
Cube = int(raw_input("What number would you like to Cube    "))
Answer2 = Cube ** 3
print "The answer is :%d" %Answer2

if Options == "Multiply":
Multiply1 = int(raw_input("What is the first number to multiply?    "))
Multiply2 = int(raw_input("What is the second number to multiply?     "))
Answer3 = Multiply1 * Multiply2
 print "The answer is :d%" %Answer3"
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Python is case-sensitive. If needs to be if. Your code also needs to be indented properly.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...