@SteveTjoa's answer is fine, but for kicks, here's a numpy one-liner:
In [19]: a
Out[19]:
array([[1, 1, 0, 0],
[0, 1, 0, 0],
[0, 1, 1, 1],
[1, 1, 1, 1]])
In [20]: a.dot(1 << arange(a.shape[-1] - 1, -1, -1))
Out[20]: array([12, 4, 7, 15])
(arange
is numpy.arange
.)
If the bits are in the opposite order, change the order of the values produced by arange
:
In [25]: a.dot(1 << arange(a.shape[-1]))
Out[25]: array([ 3, 2, 14, 15])
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