Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
216 views
in Technique[技术] by (71.8m points)

python - Why am I getting a NameError when I try to call my function?

This is my code:

import os

if os.path.exists(r'C:Genisis_AI'):
    print("Main File path exists! Continuing with startup")
else:
    createDirs()

def createDirs():
    os.makedirs(r'C:Genisis_AImemories')

When I execute this, it throws an error:

File "foo.py", line 6, in <module>
    createDirs()
NameError: name 'createDirs' is not defined

I made sure it's not a typo and I didn't misspell the function's name, so why am I getting a NameError?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can't call a function unless you've already defined it. Move the def createDirs(): block up to the top of your file, below the imports.

Some languages allow you to use functions before defining them. For example, javascript calls this "hoisting". But Python is not one of those languages.


Note that it's allowable to refer to a function in a line higher than the line that creates the function, as long as chronologically the definition occurs before the usage. For example this would be acceptable:

import os

def doStuff():
    if os.path.exists(r'C:Genisis_AI'):
        print("Main File path exists! Continuing with startup")
    else:
        createDirs()

def createDirs():
    os.makedirs(r'C:Genisis_AImemories')

doStuff()

Even though createDirs() is called on line 7 and it's defined on line 9, this isn't a problem because def createDirs executes before doStuff() does on line 12.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...