Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
226 views
in Technique[技术] by (71.8m points)

Deserialize JSON / NSDictionary to Swift objects

Is there a way to properly deserialize a JSON response to Swift objects resp. using DTOs as containers for fixed JSON APIs?

Something similar to http://james.newtonking.com/json or something like this example from Java

User user = jsonResponse.readEntity(User.class);

whereby jsonResponse.toString() is something like

{
  "name": "myUser", 
  "email": "user@example.com",
  "password": "passwordHash"
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

SWIFT 4 Update


Since you give a very simple JSON object the code prepared for to handle that model. If you need more complicated JSON models you need to improve this sample.

Your Custom Object

class Person : NSObject {
    var name : String = ""
    var email : String = ""
    var password : String = ""

    init(JSONString: String) {
        super.init()

        var error : NSError?
        let JSONData = JSONString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)

        let JSONDictionary: Dictionary = NSJSONSerialization.JSONObjectWithData(JSONData, options: nil, error: &error) as NSDictionary

        // Loop
        for (key, value) in JSONDictionary {
            let keyName = key as String
            let keyValue: String = value as String

            // If property exists
            if (self.respondsToSelector(NSSelectorFromString(keyName))) {
                self.setValue(keyValue, forKey: keyName)
            }
        }
        // Or you can do it with using 
        // self.setValuesForKeysWithDictionary(JSONDictionary)
        // instead of loop method above
    }
}

And this is how you invoke your custom class with JSON string.

override func viewDidLoad() {
    super.viewDidLoad()
    let jsonString = "{ "name":"myUser", "email":"user@example.com", "password":"passwordHash" }"
    var aPerson : Person = Person(JSONString: jsonString)
    println(aPerson.name) // Output is "myUser"
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...