What you mean by this part is possible:
new AnimalContext<a.GetType()>();
Obviously that exact syntax is wrong, and we'll get to that, but it is possible to construct an instance of a generic type at runtime when you don't know the type parameters until runtime.
What you mean by this part is not:
AnimalContext<a.GetType()> a_Context
That is, it is impossible to type a variable as a generic type if you don't know the type parameters at compile-time. Generics are compile-time constructs, and rely on having the type information available at compile-time. Given this, you lose all the benefits of generics if you don't know the types at compile-time.
Now, to construct an instance of a generic type at runtime when you don't know the type until runtime, you can say:
var type = typeof(AnimalContext<>).MakeGenericType(a.GetType());
var a_Context = Activator.CreateInstance(type);
Note that the compile-time type of a_context
is object
. You will have to cast a_context
to a type or interface that defines the methods you need to access. Often what you'll see people do here is have the generic type AnimalContext<T>
implement some interface (say IAnimalContext
) or inherit from a non-generic base class (say AnimalContext
) that defines the methods they need (so then you can cast a_context
to the interface or the non-generic base class). Another alternative is to use dynamic
. But again, keep in mind, you have none of the benefits of generic types in doing this.
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…