go - Pass method argument to function

Question

I'm curious if this is possible in Go. I have a type with multiple methods. Is it possible to have a function which takes a method argument and then call it for the type?

Here is a small example of what I would want:

package main

import (
    "fmt"
)

type Foo int

func (f Foo) A() {
    fmt.Println("A")
}
func (f Foo) B() {
    fmt.Println("B")
}
func (f Foo) C() {
    fmt.Println("C")
}

func main() {
    var f Foo
    bar := func(foo func()) {
        f.foo()
    }
    bar(A)
    bar(B)
    bar(C)
}

Go thinks type Foo has a method called foo(), rather than replacing it with the passed in method name.

Answer 1

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