Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
584 views
in Technique[技术] by (71.8m points)

java - JPA Criteria builder IN clause query

How to write criteria builder api query for below given JPQL query? I am using JPA 2.2.

SELECT * 
FROM Employee e
WHERE e.Parent IN ('John','Raj')
ORDER BY e.Parent
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

This criteria set-up should do the trick:

CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<Employee> q = cb.createQuery(Employee.class);


Root<Employee> root = q.from(Employee.class);
q.select(root);

List<String> parentList = Arrays.asList(new String[]{"John", "Raj"});

Expression<String> parentExpression = root.get(Employee_.Parent);
Predicate parentPredicate = parentExpression.in(parentList);
q.where(parentPredicate);
q.orderBy(cb.asc(root.get(Employee_.Parent));

q.getResultList();

I have used the overloaded CriteriaQuery.where method here which accepts a Predicate.. an in predicate in this case.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...