Implementing two interfaces with two default methods of the same signature in Java 8

Question

Suppose I have two interfaces:

public interface I1
{
    default String getGreeting() {
        return "Good Morning!";
    }
}

public interface I2
{
    default String getGreeting() {
        return "Good Afternoon!";
    }
}

If I want to implement both of them, what implementation will be used?

public class C1 implements I1, I2
{
    public static void main(String[] args)
    {
        System.out.println(new C1().getGreeting());
    }
}

Answer 1

This is a compile-time error. You cannot have two implementation from two interfaces.

However, it is correct, if you implement the getGreeting method in C1:

public class C1 implements I1, I2 // this will compile, bacause we have overridden getGreeting()
{
    public static void main(String[] args)
    {
        System.out.println(new C1().getGreeting());
    }

    @Override public String getGreeting()
    {
        return "Good Evening!";
    }
}

I just want to add that even if the method in I1 is abstract, and default in I2, you cannot implement both of them. So this is also a compile-time error:

public interface I1
{
    String getGreeting();
}

public interface I2
{
    default String getGreeting() {
        return "Good afternoon!";
    }
}

public class C1 implements I1, I2 // won't compile
{
    public static void main(String[] args)
    {
        System.out.println(new C1().getGreeting());
    }
}