Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
485 views
in Technique[技术] by (71.8m points)

command line - How can I generate a list of files with their absolute path in Linux?

I am writing a shell script that takes file paths as input.

For this reason, I need to generate recursive file listings with full paths. For example, the file bar has the path:

/home/ken/foo/bar

but, as far as I can see, both ls and find only give relative path listings:

./foo/bar   (from the folder ken)

It seems like an obvious requirement, but I can't see anything in the find or ls man pages.

How can I generate a list of files in the shell including their absolute paths?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

If you give find an absolute path to start with, it will print absolute paths. For instance, to find all .htaccess files in the current directory:

find "$(pwd)" -name .htaccess

or if your shell expands $PWD to the current directory:

find "$PWD" -name .htaccess

find simply prepends the path it was given to a relative path to the file from that path.

Greg Hewgill also suggested using pwd -P if you want to resolve symlinks in your current directory.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...