Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
406 views
in Technique[技术] by (71.8m points)

ecmascript 6 - Why is the response object from JavaScript fetch API a promise?

When requesting from a server with JavaScript fetch API, you have to do something like

fetch(API)
  .then(response => response.json())
  .catch(err => console.log(err))

Here, response.json() is resolving its promise.

The thing is that if you want to catch 404's errors, you have to resolve the response promise and then reject the fetch promise, because you'll only end in catch if there's been a network error. So the fetch call becomes something like

fetch(API)
  .then(response => response.ok ? response.json() : response.json().then(err => Promise.reject(err)))
  .catch(err => console.log(err))

This is something much harder to read and reason about. So my question is: why is this needed? What's the point of having a promise as a response value? Are there any better ways to handle this?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

If your question is "why does response.json() return a promise?" then @Bergi provides the clue in comments: "it waits for the body to load".

If your question is "why isn't response.json an attribute?", then that would have required fetch to delay returning its response until the body had loaded, which might be OK for some, but not everyone.

This polyfill should get you what you want:

var fetchOk = api => fetch(api)
  .then(res => res.ok ? res : res.json().then(err => Promise.reject(err)));

then you can do:

fetchOk(API)
  .then(response => response.json())
  .catch(err => console.log(err));

The reverse cannot be polyfilled.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...