Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
548 views
in Technique[技术] by (71.8m points)

javascript - How to check the depth of an object?

I'm working on a permissions system with variable depth; depending on the complexity of a page, there could be more or less levels. I searched StackOverflow to find if this has been asked before, couldn't find it.

If I have this object:

{foo:{bar:{baz : 'baa'}}}

I need it to return 3, it has 3 levels to it.

With this object:

{abc: 'xyz'} 

It would have to be 1.

This is what I have so far:

utils.depthOf = function(object, level){
    // Returns an int of the deepest level of an object
    level = level || 1;

    var key;
    for(key in object){
        if (!object.hasOwnProperty(key)) continue;

        if(typeof object[key] == 'object'){
            level++;
            level = utils.depthOf(object[key], level);
        }
    }

    return level;
}

The problem is it counts sister elements too. It's actually not getting depth, it's counting all members of an object.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Well, here you go buddy, a function that does exactly what you need!

utils.depthOf = function(object) {
    var level = 1;
    for(var key in object) {
        if (!object.hasOwnProperty(key)) continue;

        if(typeof object[key] == 'object'){
            var depth = utils.depthOf(object[key]) + 1;
            level = Math.max(depth, level);
        }
    }
    return level;
}

A lot easier than we thought it would be. The issue was how it was incremented, it shouldn't have been recursively adding, rather getting the bottom-most and adding one, then choosing the max between two siblings.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...