Javascript compare 3 values

Question

I have 3 values that I want to compare f, g and h. I have some code to check that they all equal each other and that none of them are null. I've had a look online but could not find anything that seemed to answer my query. Currently I am checking the code in the following way...

if(g == h && g == f && f == h && g != null && f != null && h != null)
{
//do something
}

This is quite long winded and I might be adding more values, so I was just wondering if there is a quicker way to check that none of the values are null and that all the values equal each other?

Thanks in advance for any help.

Answer 1

You could shorten that to

if(g === h && g === f && g !== null)
{
//do something
}

---

For an actual way to compare multiple values (regardless of their number)
(inspired by/ simplified @Rohan Prabhu answer)

function areEqual(){
   var len = arguments.length;
   for (var i = 1; i< len; i++){
      if (arguments[i] === null || arguments[i] !== arguments[i-1])
         return false;
   }
   return true;
}

and call this with

if( areEqual(a,b,c,d,e,f,g,h) )
{
//do something
}