EDIT
As of TypeScript 2.8 this is officially possible with ReturnType<T>
.
type T10 = ReturnType<() => string>; // string
type T11 = ReturnType<(s: string) => void>; // void
type T12 = ReturnType<(<T>() => T)>; // {}
type T13 = ReturnType<(<T extends U, U extends number[]>() => T)>; // number[]
See this pull request to Microsoft/TypeScript for details.
TypeScript is awesome!
Old-school hack
Ryan's answer doesn't work anymore, unfortunately. But I have modified it with a hack which I am unreasonably happy about. Behold:
const fnReturnType = (false as true) && fn();
It works by casting false
to the literal value of true
, so that the type system thinks the return value is the type of the function, but when you actually run the code, it short circuits on false
.
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