By design, getRequestURL()
gives you the full URL, missing only the query string.
In HttpServletRequest
, you can get individual parts of the URI using the methods below:
// Example: http://myhost:8080/people?lastname=Fox&age=30
String uri = request.getScheme() + "://" + // "http" + "://
request.getServerName() + // "myhost"
":" + // ":"
request.getServerPort() + // "8080"
request.getRequestURI() + // "/people"
"?" + // "?"
request.getQueryString(); // "lastname=Fox&age=30"
.getScheme()
will give you "https"
if it was a https://domain
request.
.getServerName()
gives domain
on http(s)://domain
.
.getServerPort()
will give you the port.
Use the snippet below:
String uri = request.getScheme() + "://" +
request.getServerName() +
("http".equals(request.getScheme()) && request.getServerPort() == 80 || "https".equals(request.getScheme()) && request.getServerPort() == 443 ? "" : ":" + request.getServerPort() ) +
request.getRequestURI() +
(request.getQueryString() != null ? "?" + request.getQueryString() : "");
This snippet above will get the full URI, hiding the port if the default one was used, and not adding the "?"
and the query string if the latter was not provided.
Proxied requests
Note, that if your request passes through a proxy, you need to look at the X-Forwarded-Proto
header since the scheme might be altered:
request.getHeader("X-Forwarded-Proto")
Also, a common header is X-Forwarded-For
, which show the original request IP instead of the proxys IP.
request.getHeader("X-Forwarded-For")
If you are responsible for the configuration of the proxy/load balancer yourself, you need to ensure that these headers are set upon forwarding.
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