Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
408 views
in Technique[技术] by (71.8m points)

python - How can I output what SUDs is generating/receiving?

I have the following code:

from suds.client import Client
import logging

logging.basicConfig(level=logging.INFO)
logging.getLogger('suds.client').setLevel(logging.DEBUG)
logging.getLogger('suds.transport').setLevel(logging.DEBUG)
logging.getLogger('suds.xsd.schema').setLevel(logging.DEBUG)
logging.getLogger('suds.wsdl').setLevel(logging.DEBUG)

SB_PRIVATE_ACCESS = {"PATH":"https://thisurl.com:443/services/",}

client = Client(SB_PRIVATE_ACCESS['PATH'])
print client

but I am getting 500 errors. I am trying to send what XML is being generated and received through SUDs, to the wsdl developer, but I can't figure how to output it? I have been looking in the documentation of SUDs, but can't seem to find it :/ Does anyone know how to output the raw xml that is sent and received?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

SUDS provides some convenience methods to do just that:

 client.last_sent()
 client.last_received()

These should provide you with what you need. I use them for error logging. The API doc for Client class should have any extra info you need.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...