Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
432 views
in Technique[技术] by (71.8m points)

r - Splitting a large data frame into smaller segments

I have the following data frame and I want to break it up into 10 different data frames. I want to break the initial 100 row data frame into 10 data frames of 10 rows. I could do the following and get the desired results.

df = data.frame(one=c(rnorm(100)), two=c(rnorm(100)), three=c(rnorm(100)))

df1 = df[1:10,]
df2 = df[11:20,]
df3 = df[21:30,]
df4 = df[31:40,]
df5 = df[41:50,]
...

Of course, this isn't an elegant way to perform this task when the initial data frames are larger or if there aren't an easy number of segments that it can be broken down into.

So given the above, let's say we have the following data frame.

df = data.frame(one=c(rnorm(1123)), two=c(rnorm(1123)), three=c(rnorm(1123)))

Now I want to split it into new data frames comprised of 200 rows, and the final data frame with the remaining rows. What would be a more elegant (aka 'quick') way to perform this task.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
 > str(split(df, (as.numeric(rownames(df))-1) %/% 200))
List of 6
 $ 0:'data.frame':  200 obs. of  3 variables:
  ..$ one  : num [1:200] -1.592 1.664 -1.231 0.269 0.912 ...
  ..$ two  : num [1:200] 0.639 -0.525 0.642 1.347 1.142 ...
  ..$ three: num [1:200] -0.45 -0.877 0.588 1.188 -1.977 ...
 $ 1:'data.frame':  200 obs. of  3 variables:
  ..$ one  : num [1:200] -0.0017 1.9534 0.0155 -0.7732 -1.1752 ...
  ..$ two  : num [1:200] -0.422 0.869 0.45 -0.111 0.073 ...
  ..$ three: num [1:200] -0.2809 1.31908 0.26695 0.00594 -0.25583 ...
 $ 2:'data.frame':  200 obs. of  3 variables:
  ..$ one  : num [1:200] -1.578 0.433 0.277 1.297 0.838 ...
  ..$ two  : num [1:200] 0.913 0.378 0.35 -0.241 0.783 ...
  ..$ three: num [1:200] -0.8402 -0.2708 -0.0124 -0.4537 0.4651 ...
 $ 3:'data.frame':  200 obs. of  3 variables:
  ..$ one  : num [1:200] 1.432 1.657 -0.72 -1.691 0.596 ...
  ..$ two  : num [1:200] 0.243 -0.159 -2.163 -1.183 0.632 ...
  ..$ three: num [1:200] 0.359 0.476 1.485 0.39 -1.412 ...
 $ 4:'data.frame':  200 obs. of  3 variables:
  ..$ one  : num [1:200] -1.43 -0.345 -1.206 -0.925 -0.551 ...
  ..$ two  : num [1:200] -1.343 1.322 0.208 0.444 -0.861 ...
  ..$ three: num [1:200] 0.00807 -0.20209 -0.56865 1.06983 -0.29673 ...
 $ 5:'data.frame':  123 obs. of  3 variables:
  ..$ one  : num [1:123] -1.269 1.555 -0.19 1.434 -0.889 ...
  ..$ two  : num [1:123] 0.558 0.0445 -0.0639 -1.934 -0.8152 ...
  ..$ three: num [1:123] -0.0821 0.6745 0.6095 1.387 -0.382 ...

If some code might have changed the rownames it would be safer to use:

 split(df, (seq(nrow(df))-1) %/% 200) 

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...