c# - If my struct implements IDisposable will it be boxed when used in a using statement?

Question

If my struct implements IDisposable will it be boxed when used in a using statement?

Thanks

Edit: this timedlock is a struct and implements Idisposable. http://www.interact-sw.co.uk/iangblog/2004/04/26/yetmoretimedlocking

Edit 2: Looking at the IL it seems If your struct exposes Dispose() as public, the compiler calls Dispose when an instance of the struct goes out of scope if you forget to call Dispose() (for example, you are not using the "using" statement)?

Answer 1

Per Eric Lippert:

A call to IDisposable.Dispose on a struct is generated as a constrained virtual call, which most of the time does NOT box the value.

A constrained virtual call on a value type only boxes the value if the virtual method is NOT implemented by the type. The only circumstances under which a virtual method can be unimplemented by the value type is when the method is, say, ToString, and implemented by the base class, System.ValueType.

See section 2.1 of Partition III of the CLI documentation for more detail.