Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
532 views
in Technique[技术] by (71.8m points)

currying - Curry Function in Swift

I want to make a function that return a curry function like below

func addTwoNumbers(a: Int)(b: Int) -> Int {
    return a + b
}

addTwoNumbers(4)(b: 6) // Result: 10

var add4 = addTwoNumbers(4)
add4(b: 10) // returns 14     

What is the return type of such function and how can I generate a function like this using a function that take Variadic parameters.

func generateCurry(.../*Variadic parameters*/) -> .../*curry function type*/ {
  return ...//curry function
}

I want a generic solution and not take only Int as arguments in the parmeter of the generateCurry function

let curried = curry(func(a, b, c) {
  print(a + b + c)
})
curried(1)(2)(3) //prints 6
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can achieve this pretty easily with closures:

/// Takes a binary function and returns a curried version
func curry<A,B,C>(f: (A, B) -> C) -> A -> B -> C {
    return { a in { b in f(a, b) } }
}

curry(+)(5)(6) // => 11

let add: Int -> Int -> Int = curry(+)
add(5)(6) // => 11

It would be really nice to be able to do the same thing for functions that take 3, 4 or more arguments, but without duplicating the implementation. The signature of such a function might start something like:

/// Take a function accepting N arguments and return a curried version
func curry<T>(args: T...) -> /* ? */

What would the return type be? It would change based on the input to the function. This definitely isn't possible in Swift at the moment, and I don't think it would be possible at all without some kind of macro system. But even with macros I don't think the compiler would be satisfied unless it knew the length of the list at compile-time.

Having said that, it's really straight-forward to manually overload the currying function with a version that accepts 3, 4, 5 or more parameters:

func curry<A,B,C,D>(f: (A, B, C) -> D) -> A -> B -> C -> D {
    return { a in { b in { c in f(a,b,c) } } }
}

func curry<A,B,C,D,E>(f: (A, B, C, D) -> E) -> A -> B -> C -> D -> E {
    return { a in { b in { c in { d in f(a,b,c,d) } } } }
}

// etc.

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...