Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
299 views
in Technique[技术] by (71.8m points)

html - Gradient colors in Internet Explorer

I know that Internet Explorer has some proprietary extensions so that you can do things like create divs with a gradient background. I can't remember the element name or it's usage. Does anyone have some examples or links?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The code I use for all browser gradients:

background: #0A284B;
background: -webkit-gradient(linear, left top, left bottom, from(#0A284B), to(#135887));
background: -webkit-linear-gradient(#0A284B, #135887);
background: -moz-linear-gradient(top, #0A284B, #135887);
background: -ms-linear-gradient(#0A284B, #135887);
background: -o-linear-gradient(#0A284B, #135887);
background: linear-gradient(#0A284B, #135887);
filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#0A284B', endColorstr='#135887');
zoom: 1;

You will need to specify a height or zoom: 1 to apply hasLayout to the element for this to work in IE.


Update:

Here is a LESS Mixin (CSS) version for all you LESS users out there:

.gradient(@start, @end) {
    background: mix(@start, @end, 50%);
    filter: ~"progid:DXImageTransform.Microsoft.gradient(startColorStr="@start~", EndColorStr="@end~")";
    background: -webkit-gradient(linear, left top, left bottom, from(@start), to(@end));
    background: -webkit-linear-gradient(@start, @end);
    background: -moz-linear-gradient(top, @start, @end);
    background: -ms-linear-gradient(@start, @end);
    background: -o-linear-gradient(@start, @end);
    background: linear-gradient(@start, @end);
    zoom: 1;
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...