python - Why can't PySpark find py4j.java_gateway?

Question

I installed Spark, ran the sbt assembly, and can open bin/pyspark with no problem. However, I am running into problems loading the pyspark module into ipython. I'm getting the following error:

In [1]: import pyspark
---------------------------------------------------------------------------
ImportError                               Traceback (most recent call last)
<ipython-input-1-c15ae3402d12> in <module>()
----> 1 import pyspark

/usr/local/spark/python/pyspark/__init__.py in <module>()
     61
     62 from pyspark.conf import SparkConf
---> 63 from pyspark.context import SparkContext
     64 from pyspark.sql import SQLContext
     65 from pyspark.rdd import RDD

/usr/local/spark/python/pyspark/context.py in <module>()
     28 from pyspark.conf import SparkConf
     29 from pyspark.files import SparkFiles
---> 30 from pyspark.java_gateway import launch_gateway
     31 from pyspark.serializers import PickleSerializer, BatchedSerializer, UTF8Deserializer, 
     32     PairDeserializer, CompressedSerializer

/usr/local/spark/python/pyspark/java_gateway.py in <module>()
     24 from subprocess import Popen, PIPE
     25 from threading import Thread
---> 26 from py4j.java_gateway import java_import, JavaGateway, GatewayClient
     27
     28

ImportError: No module named py4j.java_gateway

Answer 1

In my environment (using docker and the image sequenceiq/spark:1.1.0-ubuntu), I ran in to this. If you look at the pyspark shell script, you'll see that you need a few things added to your PYTHONPATH:

export PYTHONPATH=$SPARK_HOME/python/:$PYTHONPATH
export PYTHONPATH=$SPARK_HOME/python/lib/py4j-0.8.2.1-src.zip:$PYTHONPATH

That worked in ipython for me.

Update: as noted in the comments, the name of the py4j zip file changes with each Spark release, so look around for the right name.