forward declaration of a struct in C?

Question

#include <stdio.h>

struct context;

struct funcptrs{
  void (*func0)(context *ctx);
  void (*func1)(void);
};

struct context{
    funcptrs fps;
}; 

void func1 (void) { printf( "1
" ); }
void func0 (context *ctx) { printf( "0
" ); }

void getContext(context *con){
    con=?; // please fill this with a dummy example so that I can get this working. Thanks.
}

int main(int argc, char *argv[]){
 funcptrs funcs = { func0, func1 };
   context *c;
   getContext(c);
   c->fps.func0(c);
   getchar();
   return 0;
}

I am missing something here. Please help me fix this. Thanks.

Answer 1

A struct (without a typedef) often needs to (or should) be with the keyword struct when used.

struct A;                      // forward declaration
void function( struct A *a );  // using the 'incomplete' type only as pointer

If you typedef your struct you can leave out the struct keyword.

typedef struct A A;          // forward declaration *and* typedef
void function( A *a );

Note that it is legal to reuse the struct name

Try changing the forward declaration to this in your code:

typedef struct context context;

It might be more readable to do add a suffix to indicate struct name and type name:

typedef struct context_s context_t;