csv - consolidating data frames in R

Question

Hi I have a lot of CSV files to process. Each file is generated by a run of an algorithm. My data always has one key and a value like this:

csv1:

        index value
  1     1     1
  2     2     1
  3     3     1
  4     4     1
  5     5     1

csv2:

      index value
1     4     3
2     5     3
3     6     3
4     7     3
5     8     3

Now I want to aggregate these CSV data, like this:

When both files contain an identical key e.g. 5, the resulting row should contain the key both files share (5) and the mean of both values ((1+3)/2 = 2). If only one file contains a key (e.g. 2), this row is just added to the result table (key = 2, value = 1).

Something like this:

      index value
1     1     1
2     2     1
3     3     1
4     4     2 (as (1+4)/2 = 2)
5     5     2 (as (1+4)/2 = 2)
6     6     3
7     7     3
8     8     3

At first I thought rbind() does the job, but it does not aggregate the values, only concatenates the data. How can I achieve that with R?

Answer 1

Here is a solution. I am following all the excellent comments so far, and hopefully adding value by showing you how to handle any number of files. I am assuming you have all your csv files in the same directory (my.csv.dir below).

# locate the files
files <- list.files(my.csv.dir)

# read the files into a list of data.frames
data.list <- lapply(files, read.csv)

# concatenate into one big data.frame
data.cat <- do.call(rbind, data.list)

# aggregate
data.agg <- aggregate(value ~ index, data.cat, mean)

---

Edit: to handle your updated question in your comment below:

files     <- list.files(my.csv.dir)
algo.name <- sub("-.*", "", files)
data.list <- lapply(files, read.csv)
data.list <- Map(transform, data.list, algorithm = algo.name)
data.cat  <- do.call(rbind, data.list)
data.agg  <- aggregate(value ~ algorithm + index, data.cat, mean)