Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
750 views
in Technique[技术] by (71.8m points)

class - Passing an instance method as argument in PHP

I would like to create a Listener class

class Listener {
    var $listeners = array();
    
    public function add(callable $function) {
        $this->listeners[] = $function;
    }

    public function fire() {
        foreach($this->listeners as $function) {
            call_user_func($function);
        }
    }
}

class Foo {
    public function __construct($listener) {
        $listener->add($this->bar);
    }
    
    public function bar() {
        echo 'bar';
    }
}



$listener = new Listener();
$foo = new Foo($listener);

But this code fails with this error:

Notice: Undefined property: Foo::$bar in index.php on line 18

Catchable fatal error: Argument 1 passed to Listener::add() must be callable, null given, called in index.php on line 18 and defined index.php on line 5

What am I doing wrong?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
  • Before PHP 5.4, there was no type named callable, so if you use it as a type hint, it means "the class named callable". If you use PHP >= 5.4, callable is a valid hint.

  • A callable is specified by a string describing the name of the callable (a function name or a class method name for example) or an array where the first element is an instance of an object and the second element is the name of the method to be called.

For PHP < 5.4, replace

public function add(callable $function)

with:

public function add($function)

Call it with:

$listener->add(array($this, 'bar'));

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...