Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
472 views
in Technique[技术] by (71.8m points)

scope - Why is the type not accessible?

I'm trying to return a type from a fortran function. This is the code.

module somemodule
implicit none
! define a simple type
type sometype
   integer :: someint
end type sometype
! define an interface 
interface
   ! define a function that returns the previously defined type
   type(sometype) function somefunction()
   end function somefunction
end interface
contains
end module somemodule

In gfortran (4.4 & 4.5) I get the following error:

Error: The type for function 'somefunction' at (1) is not accessible

I compiled the file as:

gfortran -c ./test.F90

I tried to make the type explicitly public but that didn't help. I was planning to use a c version of the somefunction, that is why I put it in the interface section.

Why is the type not accessible?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Adding import inside the function definition fixes this. Due to what many consider a mistake in the design of the language, definitions aren't inherited inside of an interface. The "import" overrides this to achieve the sensible behavior.

interface
   ! define a function that returns the previously defined type
   type(sometype) function somefunction()
   import
   end function somefunction
end interface

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

56.8k users

...