Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
415 views
in Technique[技术] by (71.8m points)

aggregation framework - MongoDB group by values in an array field

I have my asset documents in the below format.

db.asset.find({}).limit(1).pretty()
{
    "_id" : ObjectId("54e650a10364a65f62c0df4a"),
    "_class" : "com.model.core.Asset",
    "displayName" : "Bingo Rhymes For Children + More 3D Animation Nursery Rhymes & Kids' Songs",
    "assetType" : "VIDEO",
    "active" : true,
    "originalUrl" : "https://www.youtube.com/watch?v=j-tdVvvXn9k&feature=youtube_gdata",
    "groupIds" : [ ],
    "folderIds" : [
        "54e6507b0364a65f62c0df47",
        "54e6507b0364a65f62c0df48"
    ]
}

As you can see each asset can have a collection of folderId to which it is associated with. If I want to find the folderIds along with the associated assets how does the mongo aggregate query will look like? Essentially I want to group the assets by folderId.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You first need to unwind by the folderIds field, than group by _id and push the asset _id into a list assets_id.

db.asset.aggregate([{$unwind:"$folderIds"},  {$group:{_id: "$folderIds",assets:{$push: {assets_id:"$_id"}}}}])

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...