python - What is the purpose of classmethod in this code?

Question

In django.utils.tree.py:

def _new_instance(cls, children=None, connector=None, negated=False):
    obj = Node(children, connector, negated)
    obj.__class__ = cls
    return obj
_new_instance = classmethod(_new_instance)

I don't know what classmethod does in this code sample. Can someone explain what it does and how to use it?

Answer 1

classmethod is a decorator, wrapping a function, and you can call the resulting object on a class or (equivalently) an instance thereof:

>>> class x(object):
...   def c1(*args): print 'c1', args
...   c1 = classmethod(c1)
...   @classmethod
...   def c2(*args): print 'c2', args
... 
>>> inst = x()
>>> x.c1()
c1 (<class '__main__.x'>,)
>>> x.c2()
c2 (<class '__main__.x'>,)
>>> inst.c1()
c1 (<class '__main__.x'>,)
>>> inst.c2()
c2 (<class '__main__.x'>,)

As you see, whether you define it directly or with decorator syntax, and whether you call it on the class or the instance, the classmethod always receives the class as its first argument.

One of the main uses of classmethod is to define alternative constructors:

>>> class y(object):
...   def __init__(self, astring):
...     self.s = astring
...   @classmethod
...   def fromlist(cls, alist):
...     x = cls('')
...     x.s = ','.join(str(s) for s in alist)
...     return x
...   def __repr__(self):
...     return 'y(%r)' % self.s
...
>>> y1 = y('xx')
>>> y1
y('xx')
>>> y2 = y.fromlist(range(3))
>>> y2
y('0,1,2')

Now if you subclass y, the classmethod keeps working, e.g.:

>>> class k(y):
...   def __repr__(self):
...     return 'k(%r)' % self.s.upper()
...
>>> k1 = k.fromlist(['za','bu'])
>>> k1
k('ZA,BU')