Tested & Working Version
User.select(:first,:email).group(:first,:email).having("count(*) > 1")
Also, this is a little unrelated but handy. If you want to see how times each combination was found, put .size at the end:
User.select(:first,:email).group(:first,:email).having("count(*) > 1").size
and you'll get a result set back that looks like this:
{[nil, nil]=>512,
["Joe", "test@test.com"]=>23,
["Jim", "email2@gmail.com"]=>36,
["John", "email3@gmail.com"]=>21}
Thought that was pretty cool and hadn't seen it before.
Credit to Taryn, this is just a tweaked version of her answer.
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