postgresql - Custom ORDER BY Explanation

Question

I found this some time ago and have been using it since; however, looking at it today, I realized that I do not fully understand why it works. Can someone shed some light on it for me?

ORDER BY  s.type!= 'Nails',
          s.type!= 'Bolts',
          s.type!= 'Washers',
          s.type!= 'Screws',
          s.type!= 'Staples',
          s.type!= 'Nuts', ...

If I order by s.type, it orders alphabetically. If I use the example above it uses the same order as the line positions. What I don't understand is the use of !=. If I use = it appears in the opposite order. I cannot wrap my head around the concept of this.

It would reason to me that using = in place of the !='s above would place Nails first in position, but it does not, it place it in the last. I guess my question is this: Why do i have to use !=, not = in this situation?

Answer 1

Each expression gets evaluated as a bool and treated as 0 for false and 1 for true and sorted appropriately. Even though this works, the logic is hard to follow (and thus maintain). What I use is a function that finds a value's index in an array.

ORDER BY idx(array['Nails','Bolts','Washers','Screws','Staples','Nuts'], s.type)

This is much easier to follow. Nails will be sorted first and nuts sorted last. You can see how to create the idx function in the Postgres snippets repository. http://wiki.postgresql.org/wiki/Array_Index