Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
471 views
in Technique[技术] by (71.8m points)

php - nohup:ignoring input and appending output to 'nohup.out'

I want to start my server through nohup.php but the command is not running and displays following error

nohup:ignoring input and appending output to 'nohup.out'

I am using ssh through putty, this is what i am doing

nohup php server1.php

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

That's not an error - it's normal behavior. It just informs you that once started the in/output is removed from your console.

To avoid the message you need to start it like

nohup php server1.php </dev/null &>/dev/null &

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...