Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
649 views
in Technique[技术] by (71.8m points)

python - How to return a "Tuple type" in a UDF in PySpark?

All the data types in pyspark.sql.types are:

__all__ = [
    "DataType", "NullType", "StringType", "BinaryType", "BooleanType", "DateType",
    "TimestampType", "DecimalType", "DoubleType", "FloatType", "ByteType", "IntegerType",
    "LongType", "ShortType", "ArrayType", "MapType", "StructField", "StructType"]

I have to write a UDF (in pyspark) which returns an array of tuples. What do I give the second argument to it which is the return type of the udf method? It would be something on the lines of ArrayType(TupleType())...

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

There is no such thing as a TupleType in Spark. Product types are represented as structs with fields of specific type. For example if you want to return an array of pairs (integer, string) you can use schema like this:

from pyspark.sql.types import *

schema = ArrayType(StructType([
    StructField("char", StringType(), False),
    StructField("count", IntegerType(), False)
]))

Example usage:

from pyspark.sql.functions import udf
from collections import Counter

char_count_udf = udf(
    lambda s: Counter(s).most_common(),
    schema
)

df = sc.parallelize([(1, "foo"), (2, "bar")]).toDF(["id", "value"])

df.select("*", char_count_udf(df["value"])).show(2, False)

## +---+-----+-------------------------+
## |id |value|PythonUDF#<lambda>(value)|
## +---+-----+-------------------------+
## |1  |foo  |[[o,2], [f,1]]           |
## |2  |bar  |[[r,1], [a,1], [b,1]]    |
## +---+-----+-------------------------+

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...