Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
330 views
in Technique[技术] by (71.8m points)

sql - How to get the difference between two dates rounded to hours

I'll illustrate what I would like to get in the following example:

'2010-09-01 03:00:00' - '2010-09-01 00:10:00'

Using TIMEDIFF(), we get 2 as a result. This means, it's not considering the 50 minutes left.

In this case, what I'd like to get is: 50 (minutes) / 60 = 0.83 period. Therefore, the result should be 2.83 and not 2.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
select time_to_sec(timediff('2010-09-01 03:00:00', '2010-09-01 00:10:00' )) / 3600;

+-----------------------------------------------------------------------------+
| time_to_sec(timediff('2010-09-01 03:00:00', '2010-09-01 00:10:00' )) / 3600 |
+-----------------------------------------------------------------------------+
|                                                                      2.8333 | 
+-----------------------------------------------------------------------------+

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...