python - Handle either a list or single integer as an argument

Question

A function should select rows in a table based on the row name (column 2 in this case). It should be able to take either a single name or a list of names as arguments and handle them correctly.

This is what I have now, but ideally there wouldn't be this duplicated code and something like exceptions would be used intelligently to choose the right way to handle the input argument:

def select_rows(to_select):
    # For a list
    for row in range(0, table.numRows()):
        if _table.item(row, 1).text() in to_select:
            table.selectRow(row)
    # For a single integer
    for row in range(0, table.numRows()):
        if _table.item(row, 1).text() == to_select:
            table.selectRow(row)

Answer 1

Actually I agree with Andrew Hare's answer, just pass a list with a single element.

But if you really must accept a non-list, how about just turning it into a list in that case?

def select_rows(to_select):
    if type(to_select) is not list: to_select = [ to_select ]

    for row in range(0, table.numRows()):
        if _table.item(row, 1).text() in to_select:
            table.selectRow(row)

The performance penalty for doing 'in' on a single-item list isn't likely to be high :-) But that does point out one other thing you might want to consider doing if your 'to_select' list may be long: consider casting it to a set so that lookups are more efficient.

def select_rows(to_select):
    if type(to_select) is list: to_select = set( to_select )
    elif type(to_select) is not set: to_select = set( [to_select] )

    for row in range(0, table.numRows()):
        if _table.item(row, 1).text() in to_select:
            table.selectRow(row)