Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
800 views
in Technique[技术] by (71.8m points)

create a formula in a data.table environment in R

I would like to run a regression within a data.table. The formula needs to be constructed dynamically. I have tried the following method:

x = data.table(a=1:20, b=20:1, id=1:5)
> x[,as.list(coef(lm(as.formula("a ~ b")))),by=id]
  Error in eval(expr, envir, enclos) : object 'a' not found

How does one specify the environment to be that of the actual data.table where the evaluation occurs?

EDIT: I realize I can do lm(a ~ b). I need the formula to be dynamic so it's built up as a character string. By dynamically I mean the formula can be paste0(var_1, "~", var_2) where var_1 = a and var_2 = b

Here is one solution thought I think we can do better:

txt = parse(text="as.list(coef(lm(a ~ b)))")
> x[,eval(txt),by=id]
  id (Intercept)  b
  1:  1          21 -1
  2:  2          21 -1
  3:  3          21 -1
  4:  4          21 -1
  5:  5          21 -1
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

lm can accept a character string as the formula so combine that with .SD like this:

> x[, as.list(coef(lm("a ~ b", .SD))), by = id]
   id (Intercept)  b
1:  1          21 -1
2:  2          21 -1
3:  3          21 -1
4:  4          21 -1
5:  5          21 -1

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...