python - OpenCV load video from url

Question

I have a video file (i.e. https://www.example.com/myvideo.mp4) and need to load it with OpenCV.

Doing the equivalent with an image is fairly trivial:

imgReq = requests.get("https://www.example.com/myimage.jpg")
imageBytes = np.asarray(bytearray(data), dtype=np.uint8)
loadedImage = cv2.imdecode(image, cv2.IMREAD_COLOR)

I would like to do something similar to the following (where loadedVideo will be similar to what OpenCV returns from cv2.VideoCapture):

videoReq = requests.get("https://www.example.com/myimage.mp4")
videoBytes = np.asarray(bytearray(data), dtype=np.uint8)
loadedVideo = cv2.videodecode(image, cv2.IMREAD_COLOR)

But cv2.videodecode does not exist. Any ideas?

---

Edit: Seeing as this may be a dead end with only OpenCV, I'm open for solutions that combine other imaging libraries before loading into OpenCV...if such a solution exists.

Answer 1

It seems that cv2.videocode is not a valid OpenCV API either in OpenCV 2.x or OpenCV 3.x.

Below is a sample code it works in OpenCV 3 which uses cv2.VideoCapture class.

import numpy as np
import cv2

# Open a sample video available in sample-videos
vcap = cv2.VideoCapture('https://www.sample-videos.com/video/mp4/720/big_buck_bunny_720p_2mb.mp4')
#if not vcap.isOpened():
#    print "File Cannot be Opened"

while(True):
    # Capture frame-by-frame
    ret, frame = vcap.read()
    #print cap.isOpened(), ret
    if frame is not None:
        # Display the resulting frame
        cv2.imshow('frame',frame)
        # Press q to close the video windows before it ends if you want
        if cv2.waitKey(22) & 0xFF == ord('q'):
            break
    else:
        print "Frame is None"
        break

# When everything done, release the capture
vcap.release()
cv2.destroyAllWindows()
print "Video stop"

You may check this Getting Started with Videos tutorial for more information.

Hope this help.